# Algebra 2 tutor free

Best of all, Algebra 2 tutor free is free to use, so there's no sense not to give it a try! We will also look at some example problems and how to approach them.

## The Best Algebra 2 tutor free

For example, consider the equation x2 + 6x + 9 = 0. To solve this equation by completing the square, we would first add a constant to both sides so that the left side becomes a perfect square: x2 + 6x + 9 + 4 = 4. Next, we would factor the trinomial on the left side to get (x + 3)2 = 4. Finally, we would take the square root of both sides to get x + 3 = ±2, which means that x = -3 ± 2 or x = 1 ± 2. In other words, the solutions to the original equation are x = -1, x = 3, and x = 5.

One way to solve an inequality with a fraction is to multiply both sides of the inequality by the reciprocal of the fraction. This will clear the fraction from the inequality and make it easier to solve. Another way to solve an inequality with a fraction is to divide both sides of the inequality by the fraction. This will also clear the fraction from the inequality and make it easier to solve.

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The quadratic equation is an example of a non-linear equation. Quadratics have two solutions: both of which are non-linear. The solutions to the quadratic equation are called roots of the quadratic. The general solution for the quadratic is proportional to where and are the roots of the quadratic equation. If either or , then one root is real and the other root is imaginary (a complex number). The general solution is also a linear combination of the real roots, . On the left side of this equation, you can see that only if both are equal to zero. If one is zero and one is not, then there must be a third root, which has an imaginary part and a real part. This is an imaginary root because if it had been real, it would have squared to something when multiplied by itself. The real and imaginary parts of a complex number represent its magnitude and its phase (i.e., its direction relative to some reference point), respectively. In this case, since both are real, they contribute to the magnitude of ; however, since they are in opposite phase (the imaginary part lags behind by 90° relative to the real part), they cancel each other out in phase space and have no effect on . Thus, we can say that . This representation can be written in polar form

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